PCB heating
The voltage is applied to the sides of conducting sheet placed vertically and surrounded by the still air. The flowing current heats the sheet due to resistive losses. The front and back surfaces of the sheet are cooled by the air (natural convection).
Problem Type:
Plane problem of electro-thermal coupling.
Geometry:
Given:
Data for magnetic analysis:
Sheet thickness d = 0.035 mm;
Material resistance ρ = 2·10-8 Ohm/m;
Current I = 10 A;
Material heat conductivity λ = 380 W/K·m;
Convection coefficient α = 10 W/K·m2;
Problem:
Calculate the temperature and potential distribution in a conducting sheet.
Solution:
The resistive losses are calculated in the DC conduction problem. Then these losses are transferred to the linked heat transfer problem.
The sheet is cooled by convection from the front surface F(T) = -λ·(T - T0), where λ is a convection coefficient, and T0 is an ambient temperature. We put T0 = 0 K and calculate overheating. The convection from other surfaces is ignored.
The convection is modelled by the volume heat sink: Q(T) = F(T) / d.
Results:
Current distribution in the pcb |
Temperature distribution in the pcb (overheating) |
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The pcb_current.pbm is the problem of calculating the current distribution, and pcb_heat.pbm analyzes temperature field.
 Download simulation files:
Student's version |
Professional version |
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pcb.zip |
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