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Mutual capacitance of collinear cylinders

Find the mutual capacitance between two collinear infinitively long cylinders.

Problem Type:

Plane problem of electrostatics.

Geometry:

collinear cylinders model
a = 5 mm, b = 10 mm.

Given:

Relative permittivity of vacuum ε = 1,

The charge q = 10-9 C.

Problem:

Find the mutual capacitance between two collinear infinitively long cylinders.
The analytical solution is C = [F/m]

Solution:

Each of the conductor's surfaces is marked as 'floating conductor'. These are isolated conductors with unknown potential. At some point of each conductor's surface the charge is applied. The charge is then redistributed along the conductor surface automatically.

Results:

Equipotential lines and potential distribution between collinear cylinders.
collinear cylinders voltage destribution

The capacitance can be calculated as C = q / (U2 - U1). The measured potential difference is U2-U1 = 12.4585 V.
The capacitance is C = 10-9 / 12.4585 = 8.0266·10-11 [F/m].

QuickField

Theoretical result

C, pF/m

80.266

80.261

Download Download simulation files.

QuickField 5.9

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