Plane capacitor dielectric loss - QuickField simulation example
This is an example of the plane capacitor simulation, performed with QuickField software.
How to find electric field in multilayer HV insulation?
Answer Typical applications Geometry
Given
Task
Solution
Results
Engineering question
Set up a plane-parallel QuickField AC Conduction problem for a multilayer high-voltage insulation system and evaluate electric field from computed field results.
multilayer HV insulation systems, cable insulation structures, bushing insulation assemblies
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Simulation problem
Problem Type
Plane-parallel problem of AC conduction.
Relative permittivity of dielectric ε = 10.
Voltage U = 5 V, frequency f = 1000 kHz.
Loss tangent tan(δ) = 0.01.
Calculate dielectric loss in the plane capacitor.
To calculate dielectric losses we specify effective value of electric conductivity for dielectric, that is a function of loss tangent, frequency and relative permittivity:
g = 2πf·εε0·tan(δ) = 2·3.142·1000000·10·(8.854·10-12)·0.01 = 5.56·10-6 S/m.
Active power loss is PA = 0.0695 mW per 10 mm³.
Electric current vectors and electric potential distribution in plane capacitor
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